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((1)/(3))^(3x)=729
We move all terms to the left:
((1)/(3))^(3x)-(729)=0
Domain of the equation: 3)^3x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+1/3)^3x-729=0
We multiply all the terms by the denominator
(+1-729*3)^3x=0
We add all the numbers together, and all the variables
(-2186)^3x=0
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